c^2-15c+50=0

Solution for c^2-15c+50=0 equation:

Simplifying
c2 + -15c + 50 = 0

Reorder the terms:
50 + -15c + c2 = 0

Solving
50 + -15c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + -1c)(10 + -1c) = 0

Subproblem 1
Set the factor '(5 + -1c)' equal to zero and attempt to solve:

Simplifying
5 + -1c = 0

Solving
5 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -1c = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1c = 0 + -5
-1c = 0 + -5

Combine like terms: 0 + -5 = -5
-1c = -5

Divide each side by '-1'.
c = 5

Simplifying
c = 5
Subproblem 2
Set the factor '(10 + -1c)' equal to zero and attempt to solve:

Simplifying
10 + -1c = 0

Solving
10 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1c = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1c = 0 + -10
-1c = 0 + -10

Combine like terms: 0 + -10 = -10
-1c = -10

Divide each side by '-1'.
c = 10

Simplifying
c = 10
Solution
c = {5, 10}